Integrand size = 21, antiderivative size = 83 \[ \int \frac {\cos ^2(c+d x)}{(a+a \cos (c+d x))^3} \, dx=\frac {\sin (c+d x)}{5 d (a+a \cos (c+d x))^3}-\frac {8 \sin (c+d x)}{15 a d (a+a \cos (c+d x))^2}+\frac {7 \sin (c+d x)}{15 d \left (a^3+a^3 \cos (c+d x)\right )} \]
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Time = 0.11 (sec) , antiderivative size = 83, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {2837, 2829, 2727} \[ \int \frac {\cos ^2(c+d x)}{(a+a \cos (c+d x))^3} \, dx=\frac {7 \sin (c+d x)}{15 d \left (a^3 \cos (c+d x)+a^3\right )}-\frac {8 \sin (c+d x)}{15 a d (a \cos (c+d x)+a)^2}+\frac {\sin (c+d x)}{5 d (a \cos (c+d x)+a)^3} \]
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Rule 2727
Rule 2829
Rule 2837
Rubi steps \begin{align*} \text {integral}& = \frac {\sin (c+d x)}{5 d (a+a \cos (c+d x))^3}+\frac {\int \frac {-3 a+5 a \cos (c+d x)}{(a+a \cos (c+d x))^2} \, dx}{5 a^2} \\ & = \frac {\sin (c+d x)}{5 d (a+a \cos (c+d x))^3}-\frac {8 \sin (c+d x)}{15 a d (a+a \cos (c+d x))^2}+\frac {7 \int \frac {1}{a+a \cos (c+d x)} \, dx}{15 a^2} \\ & = \frac {\sin (c+d x)}{5 d (a+a \cos (c+d x))^3}-\frac {8 \sin (c+d x)}{15 a d (a+a \cos (c+d x))^2}+\frac {7 \sin (c+d x)}{15 d \left (a^3+a^3 \cos (c+d x)\right )} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.55 \[ \int \frac {\cos ^2(c+d x)}{(a+a \cos (c+d x))^3} \, dx=\frac {\left (2+6 \cos (c+d x)+7 \cos ^2(c+d x)\right ) \sin (c+d x)}{15 a^3 d (1+\cos (c+d x))^3} \]
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Time = 0.71 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.54
method | result | size |
derivativedivides | \(\frac {\frac {\left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-\frac {2 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4 d \,a^{3}}\) | \(45\) |
default | \(\frac {\frac {\left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{5}-\frac {2 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{3}+\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4 d \,a^{3}}\) | \(45\) |
parallelrisch | \(\frac {3 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )-10 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )+15 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{60 a^{3} d}\) | \(47\) |
risch | \(\frac {2 i \left (15 \,{\mathrm e}^{4 i \left (d x +c \right )}+30 \,{\mathrm e}^{3 i \left (d x +c \right )}+40 \,{\mathrm e}^{2 i \left (d x +c \right )}+20 \,{\mathrm e}^{i \left (d x +c \right )}+7\right )}{15 d \,a^{3} \left ({\mathrm e}^{i \left (d x +c \right )}+1\right )^{5}}\) | \(69\) |
norman | \(\frac {\frac {\tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{4 d a}+\frac {\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )}{3 d a}-\frac {\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )}{30 d a}-\frac {\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )}{15 d a}+\frac {\tan ^{9}\left (\frac {d x}{2}+\frac {c}{2}\right )}{20 d a}}{a^{2} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )^{2}}\) | \(114\) |
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Time = 0.24 (sec) , antiderivative size = 75, normalized size of antiderivative = 0.90 \[ \int \frac {\cos ^2(c+d x)}{(a+a \cos (c+d x))^3} \, dx=\frac {{\left (7 \, \cos \left (d x + c\right )^{2} + 6 \, \cos \left (d x + c\right ) + 2\right )} \sin \left (d x + c\right )}{15 \, {\left (a^{3} d \cos \left (d x + c\right )^{3} + 3 \, a^{3} d \cos \left (d x + c\right )^{2} + 3 \, a^{3} d \cos \left (d x + c\right ) + a^{3} d\right )}} \]
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Time = 1.04 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.82 \[ \int \frac {\cos ^2(c+d x)}{(a+a \cos (c+d x))^3} \, dx=\begin {cases} \frac {\tan ^{5}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{20 a^{3} d} - \frac {\tan ^{3}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{6 a^{3} d} + \frac {\tan {\left (\frac {c}{2} + \frac {d x}{2} \right )}}{4 a^{3} d} & \text {for}\: d \neq 0 \\\frac {x \cos ^{2}{\left (c \right )}}{\left (a \cos {\left (c \right )} + a\right )^{3}} & \text {otherwise} \end {cases} \]
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Time = 0.23 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.81 \[ \int \frac {\cos ^2(c+d x)}{(a+a \cos (c+d x))^3} \, dx=\frac {\frac {15 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {10 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {3 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}}}{60 \, a^{3} d} \]
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Time = 0.31 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.55 \[ \int \frac {\cos ^2(c+d x)}{(a+a \cos (c+d x))^3} \, dx=\frac {3 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 10 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 15 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{60 \, a^{3} d} \]
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Time = 14.54 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.54 \[ \int \frac {\cos ^2(c+d x)}{(a+a \cos (c+d x))^3} \, dx=\frac {\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )\,\left (3\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4-10\,{\mathrm {tan}\left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2+15\right )}{60\,a^3\,d} \]
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